From: Metabolic modelling of polyhydroxyalkanoate copolymers production by mixed microbial cultures
Process description
VFA
Oxygen
Cell growth on acetate
Y X , A c S = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 4 ⋅ δ + 2 ⋅ K 1 + 1.27 ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemywaK1aaSbaaSqaaKqbaoaalmaabaGaemiwaGLaeiilaWIaemyqaeKaem4yamgabaGaem4uamfaaaWcbeaakiabg2da9KqbaoaalaaabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGOnayJaeG4naCJaeyyXICTaemyEaKNaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeG4mamJaeG4mamJaeyyXICTaeeyEaKNaeyOeI0IaeGymaeJaeiykaKcabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGOmaiJaeyyXICTaem4saS0aaSbaaeaacqaIXaqmaeqaaiabgUcaRiabigdaXiabc6caUiabikdaYiabiEda3iabcMcaPaaaaaa@63F2@
Y X , A c O 2 = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 0.33 ⋅ y ⋅ K 1 − 0.12 ⋅ y + 2.27 + 2 ⋅ K 1 ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=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@7458@
Cell growth on propionate
Y X , Pr o p S = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 4 ⋅ δ + 2 ⋅ K 2 + 0.71 ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemywaK1aaSbaaSqaaKqbaoaalmaabaGaemiwaGLaeiilaWIagiiuaaLaeiOCaiNaem4Ba8MaemiCaahabaGaem4uamfaaaWcbeaakiabg2da9KqbaoaalaaabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGOnayJaeG4naCJaeyyXICTaemyEaKNaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeG4mamJaeG4mamJaeyyXICTaeeyEaKNaeyOeI0IaeGymaeJaeiykaKcabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGOmaiJaeyyXICTaem4saS0aaSbaaeaacqaIYaGmaeqaaiabgUcaRiabicdaWiabc6caUiabiEda3iabigdaXiabcMcaPaaaaaa@66FC@
Y X , Pr o p O 2 = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 0.33 ⋅ y ⋅ K 2 − 0.22 ⋅ y + 1.71 + 2 ⋅ K 2 ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=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@7766@
PHB Storage
Y P H B S = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 4 ⋅ 5 ⋅ δ + 1 ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemywaK1aaSbaaSqaaKqbaoaalmaabaGaemiuaaLaemisaGKaemOqaieabaGaem4uamfaaaWcbeaakiabg2da9KqbaoaalaaabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGOnayJaeG4naCJaeyyXICTaemyEaKNaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeG4mamJaeG4mamJaeyyXICTaeeyEaKNaeyOeI0IaeGymaeJaeiykaKcabaGaeiikaGIaeGinaqJaeyyXICTaeGynauJaeyyXICTaeqiTdqMaey4kaSIaeGymaeJaeiykaKcaaaaa@5CF0@
Y P H B O 2 = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 2.12 − 0.21 ⋅ y ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemywaK1aaSbaaSqaaKqbaoaalmaabaGaemiuaaLaemisaGKaemOqaieabaGaem4ta8KaeGOmaidaaaWcbeaakiabg2da9KqbaoaalaaabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGOnayJaeG4naCJaeyyXICTaemyEaKNaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeG4mamJaeG4mamJaeyyXICTaeeyEaKNaeyOeI0IaeGymaeJaeiykaKcabaGaeiikaGIaeGOmaiJaeiOla4IaeGymaeJaeGOmaiJaeyOeI0IaeGimaaJaeiOla4IaeGOmaiJaeGymaeJaeyyXICTaemyEaKNaeiykaKcaaaaa@5FFF@
PHV Storage
Y P H V S = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 4 ⋅ 8 ⋅ δ + 0.8 ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemywaK1aaSbaaSqaaKqbaoaalmaabaGaemiuaaLaemisaGKaemOvayfabaGaem4uamfaaaWcbeaakiabg2da9KqbaoaalaaabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGOnayJaeG4naCJaeyyXICTaemyEaKNaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeG4mamJaeG4mamJaeyyXICTaeeyEaKNaeyOeI0IaeGymaeJaeiykaKcabaGaeiikaGIaeGinaqJaeyyXICTaeGioaGJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGioaGJaeiykaKcaaaaa@5EFE@
Y P H V O 2 = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 2 − 0.27 ⋅ y ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemywaK1aaSbaaSqaaKqbaoaalmaabaGaemiuaaLaemisaGKaemOvayfabaGaem4ta8KaeGOmaidaaaWcbeaakiabg2da9KqbaoaalaaabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGOnayJaeG4naCJaeyyXICTaemyEaKNaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeG4mamJaeG4mamJaeyyXICTaeeyEaKNaeyOeI0IaeGymaeJaeiykaKcabaGaeiikaGIaeGOmaiJaeyOeI0IaeGimaaJaeiOla4IaeGOmaiJaeG4naCJaeyyXICTaemyEaKNaeiykaKcaaaaa@5D6D@
PH2MV Storage
Y P H 2 M V S = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 5 ⋅ δ + 0.67 ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemywaK1aaSbaaSqaaKqbaoaalmaabaGaemiuaaLaemisaGKaeGOmaiJaemyta0KaemOvayfabaGaem4uamfaaaWcbeaakiabg2da9KqbaoaalaaabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGOnayJaeG4naCJaeyyXICTaemyEaKNaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeG4mamJaeG4mamJaeyyXICTaeeyEaKNaeyOeI0IaeGymaeJaeiykaKcabaGaeiikaGIaeGynauJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGOnayJaeG4naCJaeiykaKcaaaaa@5EC5@
Y P H 2 M V O 2 = ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ( 1.92 − 0.31 ⋅ y ) MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemywaK1aaSbaaSqaaKqbaoaalmaabaGaemiuaaLaemisaGKaeGOmaiJaemyta0KaemOvayfabaGaem4ta8KaeGOmaidaaaWcbeaakiabg2da9KqbaoaalaaabaGaeiikaGIaeGinaqJaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeGOnayJaeG4naCJaeyyXICTaemyEaKNaeyyXICTaeqiTdqMaey4kaSIaeGimaaJaeiOla4IaeG4mamJaeG4mamJaeyyXICTaeeyEaKNaeyOeI0IaeGymaeJaeiykaKcabaGaeiikaGIaeGymaeJaeiOla4IaeGyoaKJaeGOmaiJaeyOeI0IaeGimaaJaeiOla4IaeG4mamJaeGymaeJaeyyXICTaemyEaKNaeiykaKcaaaaa@624C@
Maintenance
m S = 2 ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ⋅ m A T P MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemyBa02aaSbaaSqaaiabdofatbqabaGccqGH9aqpjuaGdaWcaaqaaiabikdaYaqaaiabcIcaOiabisda0iabgwSixlabes7aKjabgUcaRiabicdaWiabc6caUiabiAda2iabiEda3iabgwSixlabdMha5jabgwSixlabes7aKjabgUcaRiabicdaWiabc6caUiabiodaZiabiodaZiabgwSixlabbMha5jabgkHiTiabigdaXiabcMcaPaaacqGHflY1cqWGTbqBdaWgaaqaaiabdgeabjabdsfaujabdcfaqbqabaaaaa@5597@
m O 2 = ( 2 + 0.33 ⋅ y ) ( 4 ⋅ δ + 0.67 ⋅ y ⋅ δ + 0.33 ⋅ y − 1 ) ⋅ m A T P MathType@MTEF@5@5@+=feaagaart1ev2aaatCvAUfKttLearuWrP9MDH5MBPbIqV92AaeXatLxBI9gBaebbnrfifHhDYfgasaacPC6xNi=xH8viVGI8Gi=hEeeu0xXdbba9frFj0xb9qqpG0dXdb9aspeI8k8fiI+fsY=rqGqVepae9pg0db9vqaiVgFr0xfr=xfr=xc9adbaqaaeGaciGaaiaabeqaaeqabiWaaaGcbaGaemyBa02aaSbaaSqaaiabd+eapjabikdaYaqabaGccqGH9aqpjuaGdaWcaaqaaiabcIcaOiabikdaYiabgUcaRiabicdaWiabc6caUiabiodaZiabiodaZiabgwSixlabdMha5jabcMcaPaqaaiabcIcaOiabisda0iabgwSixlabes7aKjabgUcaRiabicdaWiabc6caUiabiAda2iabiEda3iabgwSixlabdMha5jabgwSixlabes7aKjabgUcaRiabicdaWiabc6caUiabiodaZiabiodaZiabgwSixlabbMha5jabgkHiTiabigdaXiabcMcaPaaacqGHflY1cqWGTbqBdaWgaaqaaiabdgeabjabdsfaujabdcfaqbqabaaaaa@6094@